In "The Guidebook for Lineman and Cablemen" on page 522 under calculating tension on a loaded down guy is that formula correct? For the life of me i can't get their formula to work with their numbers based on their figure 15-39 on page 523.
don't recall ever using the formula.......seems like we pulled em until we got the pole where we needed or wanted it.....
on many single phase DE and angles, we raked the pole back, made the down guy up and then after we got the wire pulled in, if we needed more, we just took some more up on the downguy.........
We might have been cheating a little
Old Lineman Never Die......We Just Don't Raise Our Booms As Often
Guy Tension = T X square root of L sq. + H sq. / L
H= height of guy attachment
L= length of guy lead
T= tension of the conductors held by the down guy
Their figure has the guy attachment 50ft. from ground level, guy length at 58ft., guy lead at 30 ft. and conductor tension at 1,000lbs.
so their answer to their figure is
Guy Tension = 1,000 X square root of 30 sq. + 50 sq. / 30 = 1,944lbs.
I don't think my brain could take the calculations but heres what linemen need to see. I think!
Change the lead from 30 ft. to 20 ft. and re-calculate.
Why I say this is that often there isn't enough easement for a proper lead and I believe that is the reason the proper sag gets lost.
The Old Lineman